A) \[{{S}_{2}}O_{4}^{2-}\]
B) \[{{S}_{2}}O_{5}^{2-}\]
C) \[{{S}_{2}}O_{3}^{2-}\]
D) \[{{S}_{2}}O_{7}^{2-}\]
Correct Answer: D
Solution :
in\[{{S}_{2}}O_{7}^{2-}\]ion the two sulphur atoms are linked through an oxygen atom. Each sulphur atom is further linked with oxygen atoms. Its structure is: \[^{-}O-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{S}}}\,-O-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{S}}}\,-{{O}^{-}}\] In all other ions\[SS\] bond is present \[{{S}_{2}}O_{4}^{2-}ion{{\to }^{-}}O-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}\,-{{O}^{-}}\] \[{{S}_{2}}O_{5}^{2-}ion{{\to }^{-}}O-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{S}}}\,-O-\underset{{}}{\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{S}}}\,-{{O}^{-}}\] \[{{S}_{2}}O_{3}^{2-}ion{{\to }^{-}}O-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{S}}}\,-{{O}^{-}}\]
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