MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    A ray falls on a prism ABC W = BC) and   travels as shown in figure. The least value of refractive index of material of the prism,   should be:                    

    A) \[1.5\]                                  

    B) \[\sqrt{2}\]              

    C) \[1.33\]                               

    D) \[\sqrt{3}\]

    Correct Answer: B

    Solution :

    \[AB=BC\] \[\therefore \]  \[\angle A=\angle C={{45}^{o}}\] MN is normal drawn at the point of incidence. By geometry \[\angle LMN=45{}^\circ \] The ray is suffering total internal reflection, \[\therefore \]  \[C=45{}^\circ \] So,          \[\mu =\frac{1}{\sin C}\]                 \[=\frac{1}{\sin {{45}^{o}}}=\frac{1}{1/\sqrt{2}}=\sqrt{2}\]


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