A) \[N{{O}_{2}}\]
B) NO
C) \[{{N}_{2}}{{O}_{5}}\]
D) \[{{N}_{2}}O\]
Correct Answer: A
Solution :
Lead nitrate on heating gives lead oxide, nitrogen di-oxide with evolution of\[{{O}_{2}}\]gas. \[2Pb{{(N{{O}_{3}})}_{2}}\xrightarrow{\Delta }2PbO+4N{{O}_{2}}+{{O}_{2}}\]
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