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MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    Escape velocity from a planet is \[{{v}_{e.}}\] If its mass is increased to 8 times and its radius is increased to2 times, then the new escape        velocity would be :

    A) \[{{v}_{e.}}\]                                     

    B) \[\sqrt{2}{{v}_{e.}}\]

    C) \[2{{v}_{e.}}\]                                  

    D) \[2\sqrt{2}{{v}_{e.}}\]

    Correct Answer: C

    Solution :

    Escape velocity\[{{v}_{e}}=\frac{\sqrt{2G{{M}_{e}}}}{{{R}_{e}}}\] New escape velocity\[v_{e}^{'}=\frac{\sqrt{2G(8{{M}_{e}})}}{{{R}_{e}}}\]                                                 \[=2\frac{\sqrt{2G{{M}_{e}}}}{{{R}_{e}}}=2{{v}_{e}}\]


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