A) 3
B) 5
C) 6
D) 4
Correct Answer: A
Solution :
The electronic configuration of \[Mn(25)=1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{6}}3{{s}^{2}}3{{p}^{6}},\text{ }3{{d}^{5}},\text{ }4{{s}^{2}}\] The electronic configuration of \[M{{n}^{4+}}(25-4=21)=1{{s}^{2}}\text{ }2{{s}^{2}},\text{ }2{{p}^{6}}\] \[3{{s}^{2}},3{{p}^{6}},3{{d}^{3}},4{{s}^{0}}\] Thus\[M{{n}^{4+}}\]has three unpaired electronsYou need to login to perform this action.
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