A) 4
B) 27
C) 4/27
D) 1/27
Correct Answer: B
Solution :
\[N{{H}_{2}}COON{{H}_{4}}(s)2N{{H}_{3}}(g)+C{{O}_{2}}(g)\] On applying the law of mass action to this heterogeneous system \[{{K}_{p}}=\frac{P_{N{{H}_{3}}}^{2}\times {{P}_{C{{O}_{2}}}}}{{{P}_{N{{H}_{2}}COON{{H}_{4}}}}(s)}\] Or \[{{K}_{p}}=P_{N{{H}_{3}}}^{2}\times {{P}_{C{{O}_{2}}}}\] \[={{3}^{2}}\times 3\] \[=9\times 3=27\]You need to login to perform this action.
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