MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    Graph between velocity and displacement of   particle, executing SHM is :

    A) a straight line                    

    B) a parabola

    C) a hyperbola      

    D) an ellipse

    Correct Answer: D

    Solution :

    Displacement \[y=a\sin \omega t\] Velocity                \[v=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\] Or                           \[{{v}^{2}}={{\omega }^{2}}({{a}^{2}}-{{y}^{2}})\] Or                           \[\frac{{{v}^{2}}}{{{\omega }^{2}}}={{a}^{2}}-{{y}^{2}}\]                                 \[\frac{{{v}^{2}}}{{{\omega }^{2}}{{a}^{2}}}+\frac{{{y}^{2}}}{{{a}^{2}}}=1\]This is the equation of ellipse.


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