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MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    3 identical bulbs are connected in series and these together dissipate a power P. If now the bulbs are connected in parallel, then the              power dissipated will be :

    A) P/3                                        

    B) 3P

    C) 9P                                          

    D) P/9

    Correct Answer: C

    Solution :

    Let the resistance of each bulb is R. Then, total resistance in series\[=3R\] \[\therefore \]  \[P=\frac{{{V}^{2}}}{3R}\] In parallel, total resistance \[=\frac{R}{3}\] \[\therefore \]Power dissipated \[P'=\frac{{{V}^{2}}}{R/3}\] \[=\frac{3{{V}^{2}}}{R}\] \[=9\left( \frac{{{V}^{2}}}{3R} \right)\]   \[=9P\]


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