MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
     A block is moving up an inclined plane of  inclination 60° with velocity of 20 m/s and stops after 2s. If \[g=20m/{{s}^{2}}\]then the approximate of value of coefficient of friction is :

    A) 3                                             

    B) 3.3

    C) 0.27                                       

    D) 0.33

    Correct Answer: C

    Solution :

    Retardation\[=g(\sin {{60}^{o}}+\mu \cos {{60}^{o}})\] \[=10\left( \frac{\sqrt{3}}{2}+\frac{\mu }{2} \right)\] \[=5(\sqrt{3}+\mu )\] From \[v=u-at\]                 \[0=20-5(\sqrt{3}+\mu )\times 2\] \[(\sqrt{3}+\mu )=2\]                 \[\mu =2-\sqrt{3}\]                 \[=2-1.732=0.27\]


You need to login to perform this action.
You will be redirected in 3 sec spinner