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MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    A body executing SHM has its velocity 10 cm/s   and 7 cm/s, when its displacements from the     mean position are 3 cm and 4 cm respectively. The length of path is:

    A) 10cm                                    

    B) 9.5 cm

    C) 4cm                                       

    D) 11.36cm

    Correct Answer: D

    Solution :

    \[v=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\] \[\frac{{{v}_{2}}}{{{v}_{1}}}=\frac{{{a}^{2}}-16}{{{a}^{2}}-9}\] \[\therefore \] \[a=5.68\text{ }cm\] Length of path \[=2a=2\times 5.68=11.36\text{ }cm\]


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