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MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    A light source approaches the observer with velocity 0.5 c. Doppler's shift for light of wavelength \[5500\overset{o}{\mathop{\text{A}}}\,\] is :

    A) \[616\overset{o}{\mathop{\text{A}}}\,\]

    B) \[1833\overset{o}{\mathop{\text{A}}}\,\]

    C) \[5500\overset{o}{\mathop{\text{A}}}\,\]          

    D) \[6160\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: B

    Solution :

    \[v'=\frac{c+v}{c}.v\] \[\Rightarrow \]               \[\frac{v'}{v}=\frac{c+v}{c}=\frac{\lambda }{\lambda '}\]               \[\lambda '=\frac{\lambda c}{c+v}\]                \[=\frac{5500c}{c+0.5c}\]                 \[3667\overset{o}{\mathop{\text{A}}}\,\] \[\Delta \lambda =5500-3667\] \[1833\overset{o}{\mathop{\text{A}}}\,\]


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