A) 8 V
B) 6 V
C) 4V
D) 12V
Correct Answer: A
Solution :
\[{{\lambda }_{p}}={{\lambda }_{\alpha }}\] \[\frac{h}{\sqrt{2{{m}_{p}}{{Q}_{p}}{{V}_{p}}}}=\frac{h}{\sqrt{2{{m}_{\alpha }}{{Q}_{\alpha }}{{V}_{\alpha }}}}\] \[{{m}_{p}}{{Q}_{p}}{{V}_{p}}={{m}_{\alpha }}{{Q}_{\alpha }}{{V}_{\alpha }}\] \[{{V}_{p}}=\left( \frac{{{m}_{\alpha }}}{{{m}_{p}}} \right)\left( \frac{{{Q}_{\alpha }}}{{{Q}_{p}}} \right).{{V}_{\alpha }}\] \[=4\times 2{{V}_{\alpha }}\] \[=8V\]
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