A) 6
B) 5
C) 7.5
D) 10
Correct Answer: B
Solution :
Magnification of compound microscope \[M={{m}_{o}}\times {{m}_{e}}\] \[\Rightarrow \] \[30={{m}_{o}}\times {{m}_{e}}\] \[{{m}_{o}}=\]magnification of objective lens \[{{m}_{e}}=\]magnification of eye lens For eye lens \[{{m}_{e}}=\left( 1+\frac{D}{{{f}_{e}}} \right)\] \[=1+\frac{25}{5}\] \[=6\] \[\therefore \] \[30={{m}_{o}}\times 6\] \[\Rightarrow \] \[{{m}_{o}}=5\]
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