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MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    For an electron, if the uncertainty in velocity is \[\Delta v,\]the uncertainty in its position\[(\Delta x)\]is given by:

    A)  \[\frac{hm}{4\pi \Delta v}\]                       

    B)  \[\frac{4\pi }{hm\Delta v}\]

    C)   \[\frac{h}{4\pi m\Delta v}\]                      

    D) \[\frac{4\pi m}{h\Delta v}\]

    Correct Answer: C

    Solution :

                     According to Heisenberg's uncertainty principle \[\Delta x.\Delta p\ge \frac{h}{4\pi }\]                   \[(\Delta p=m\Delta v)\] \[\Delta x.m\Delta v\ge \frac{h}{4\pi }\]                               \[\Delta x=\frac{h}{4\pi m\pi v}\]


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