A) 0.5s
B) 1.5s
C) 3.5s
D) 3.4s
Correct Answer: B
Solution :
Velocity on hitting the surface \[=\sqrt{2\times 9.8\times 4.9}\] \[=9.8m/s\] Velocity after first bounce \[v=\frac{3}{4}\times 9.8\] Time taken from first bounce to the second bounce \[=\frac{2v}{g}=2\times \frac{3}{4}\times 9.8\times \frac{1}{9.8}=1.5\,s\]You need to login to perform this action.
You will be redirected in
3 sec