A) 0.1J
B) 0.2J
C) 0.3J
D) 0.4J
Correct Answer: A
Solution :
\[F=\frac{YA.\Delta L}{L}\] Work done \[=\frac{1}{2}F.\Delta L\] \[=\frac{1}{2}\frac{YA.\,\Delta {{L}^{2}}}{L}\] \[=\frac{2\times {{10}^{11}}\times {{10}^{-6}}\times {{10}^{-6}}}{2\times 1}\] \[=0.1\,J\]You need to login to perform this action.
You will be redirected in
3 sec