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MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    \[N{{H}_{4}}COON{{H}_{2}}(s)(g)+C{{O}_{2}}(g,)\]if equlibrium pressure is 3 atm for the above reaction.\[{{K}_{p}}\]for the reaction is:

    A)  4                                            

    B)  27

    C)  4/27                                     

    D)  1/27

    Correct Answer: B

    Solution :

                    \[N{{H}_{2}}COON{{H}_{4}}(s)2N{{H}_{3}}(g)+C{{O}_{2}}(g)\] On applying the law of mass action to this heterogeneous system \[{{K}_{p}}=\frac{P_{N{{H}_{3}}}^{2}\times {{P}_{C{{O}_{2}}}}}{{{P}_{N{{H}_{2}}COON{{H}_{4}}}}(s)}\] Or           \[{{K}_{p}}=P_{N{{H}_{3}}}^{2}\times {{P}_{C{{O}_{2}}}}\]                 \[={{3}^{2}}\times 3\]    \[=9\times 3=27\]


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