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MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    If hydrogen electrode dipped in two solution of\[pH=3\]and\[pH=6\]and salt bridge is connected, the emf of resulting cell is:

    A)  0.177V                                

    B)  0.3V

    C)   0.052V               

    D)  0.104V

    Correct Answer: A

    Solution :

                     \[[{{H}^{+}}]\]of first solution \[={{10}^{-pH}}={{10}^{-3}}\] \[[{{H}^{+}}]\]of second solution\[={{10}^{-6}}\] We know, \[E_{cell}^{o}=-0.059\log \frac{{{10}^{-6}}}{{{10}^{-3}}}\]                 \[=-0.059\log {{10}^{-3}}\]                 \[=-0.059\times -3\log 10\]                 \[=-0.059\times -3\times 1\] \[=+0.177V\]


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