A) 200 Hz
B) 204 Hz
C) 196 Hz
D) none of these
Correct Answer: C
Solution :
Each tuning fork gives 4 beats/s with its previous tuning fork, i.e., the difference between frequency of any two consecutive tuning forks is 4. \[\therefore \] \[{{f}_{n}}={{f}_{1}}+(n-1)d\] \[\Rightarrow \] \[2f=f+(50-1)\times 4\] \[\Rightarrow \] \[f=49-4\] \[f=196\,Hz\]You need to login to perform this action.
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