A) 1
B) 2
C) 4
D) 0.001
Correct Answer: D
Solution :
We know, \[{{v}_{rms}}=\sqrt{\frac{3PV}{M}}\] \[=\sqrt{\frac{3RT}{M}}\] Given \[{{v}_{rms}}=30{{R}^{1/2}}\] \[T=273+27=300K\] \[30{{R}^{1/2}}=\sqrt{\frac{3RT}{M}}\] \[\sqrt{{{30}^{2}}}R=\sqrt{\frac{3RT}{M}}\] \[30\times 30\times R=\frac{3\times R\times 300}{M}\] \[M=\frac{3\times R\times 300}{30\times 30\times R}\] \[=1g=0.001\,kg\]
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