A) \[2.5\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]
B) \[50\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]
C) \[2.5\times {{10}^{-3}}mol\,{{L}^{-1}}{{s}^{-1}}\]
D) \[1.0\times {{10}^{-3}}mol\,{{L}^{-1}}{{s}^{-1}}\]
Correct Answer: A
Solution :
\[A+2B\xrightarrow{{}}C+D\]for this reaction \[-\frac{d[A]dt}{{}}=-\frac{1}{2}\frac{d[B]}{dt}=+\frac{d[C]}{dt}=+\frac{d[D]}{dt}\] if \[-\frac{d[A]}{dt}=5\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\] then \[-\frac{1}{2}\frac{d[B]}{dt}=\frac{5\times {{10}^{-4}}}{2}\] \[=2.5\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]
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