A) \[E=2{{E}_{a}}\]
B) \[E{{ }_{a}}=2{{E}_{e}}\]
C) \[E{{ }_{a}}={{E}_{e}}\]
D) none of these
Correct Answer: B
Solution :
\[{{E}_{a}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2p}{{{r}^{3}}}\] and \[{{E}_{e}}=\frac{1}{4\pi {{\varepsilon }_{0}}}=\frac{p}{{{r}^{3}}}\] \[\therefore \] \[{{E}_{a}}=2{{E}_{e}}\]You need to login to perform this action.
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