A) \[ROC{{H}_{3}}\]
B) \[RC{{H}_{2}}OH\]
C) \[ROHC{{N}_{2}}{{N}_{2}}\]
D) \[RC{{H}_{2}}C{{H}_{3}}\]
Correct Answer: A
Solution :
In the presence of tetrafluoroboric acid, alcohols react with diazomethane\[(C{{H}_{2}}{{N}_{2}})\]to form methyl ethers in excellent yield. \[\underset{alcohaol}{\mathop{ROH}}\,+\underset{\begin{smallmatrix} diazo \\ methane \end{smallmatrix}}{\mathop{C{{H}_{2}}{{N}_{2}}}}\,\xrightarrow{HB{{F}_{4}}}\underset{\begin{smallmatrix} methoxy \\ ethane \\ (ethar) \end{smallmatrix}}{\mathop{ROC{{H}_{3}}}}\,+{{N}_{2}}\]
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