A) 2.5
B) 1
C) 5
D) 0.5
Correct Answer: A
Solution :
In\[Mn{{O}_{4}}\]the oxidation number of\[Mn\]is +7. \[\therefore \] \[\overset{+7}{\mathop{Mn}}\,+5{{e}^{-}}\xrightarrow{{}}\overset{+2}{\mathop{Mn}}\,\] In the reaction 5 electrons are involved. Hence, 5 faraday will be needed for the reduction of 1 mole of\[MnO_{4}^{-}\]. Therefore, for 0.5 mole of \[MnO_{4}^{-}\]number of faraday required = 2.5 FYou need to login to perform this action.
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