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MGIMS WARDHA MGIMS WARDHA Solved Paper-2007

  • question_answer
    Ordinary light incident on a glass slab at the polarising angle suffers a deviation of 220. The value of the angle of refraction in glass in this case is

    A) \[56{}^\circ\]

    B) \[68{}^\circ\]

    C) \[34{}^\circ\]

    D) \[22{}^\circ\]

    Correct Answer: C

    Solution :

    Deviation\[={{i}_{p}}-r={{22}^{o}}\]                          ...(i) Also,          \[{{i}_{p}}+r={{90}^{o}}\]                         ...(ii) Solving Eqs. (i) and (ii), we get\[r=34{}^\circ \]


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