MGIMS WARDHA MGIMS WARDHA Solved Paper-2007

  • question_answer
    A particle of mass m at rest decays into two particles of masses \[{{m}_{1}}\]and \[{{m}_{2}}\] having non-zero velocities. The ratio of de-Broglie wavelengths of the particles\[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\]is

    A) \[\frac{{{m}_{1}}}{{{m}_{2}}}\]                                 

    B) \[\frac{{{m}_{2}}}{{{m}_{1}}}\]

    C) \[1.0\]                                  

    D) \[\sqrt{\frac{{{m}_{2}}}{{{m}_{1}}}}\]

    Correct Answer: C

    Solution :

    From law of conservation of momentum \[P={{P}_{1}}+{{P}_{2}}\] Initial momentum, \[p=0\] \[\therefore \]  \[{{P}_{1}}=-{{P}_{2}}\] or           \[|{{P}_{1}}|=|{{P}_{2}}|\]  de-Broglie wavelength, \[\lambda =\frac{h}{|P|}\] \[\Rightarrow \]               \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{|{{P}_{2}}|}{|{{P}_{1}}|}=1\]


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