A) 25V
B) 15V
C) 12V
D) 10V
Correct Answer: B
Solution :
If grid potential be\[{{V}_{g}}\]and plate potential be\[{{V}_{p}},\]then the plate current i p is given by \[{{i}_{p}}=k{{\left( {{V}_{g}}+\frac{{{V}_{p}}}{\mu } \right)}^{3/2}}\]where\[k\]is a constant and\[\mu \]is amplification factor, of the given value. If\[{{i}_{p}}=0,\]then \[{{V}_{g}}+\frac{{{V}_{p}}}{\mu }=0\Rightarrow {{V}_{g}}=-\frac{{{V}_{p}}}{\mu }\] Given, \[{{V}_{p}}=300V,\mu =20\] \[\therefore \] \[{{V}_{g}}=\frac{300}{20}=15V\]
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