2. Solved Papers
  3. MGIMS WARDHA

MGIMS WARDHA MGIMS WARDHA Solved Paper-2007

  • question_answer
    An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed will be

    A) \[\frac{2eV}{m}\]                                           

    B) \[V\sqrt{\frac{e}{m}}\]

    C) \[\sqrt{\frac{3eV}{m}}\]                                              

    D) \[\sqrt{\frac{2eV}{m}}\]

    Correct Answer: D

    Solution :

    Kinetic energy of electron = eV \[\Rightarrow \]               \[\frac{1}{2}m{{v}^{2}}=eV\] \[\Rightarrow \]               \[v=\sqrt{\frac{2eV}{m}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner