A) 2.2
B) 2.0
C) 0.3
D) 1.7
Correct Answer: D
Solution :
\[0.02\,M\,HCl=2\times {{10}^{-2}}M\,HCl\] \[[{{H}^{+}}]=2\times {{10}^{-2}}\] \[pH=-\log [{{H}^{+}}]\] \[=-\log [2\times {{10}^{-2}}]\] \[=-\log 2+2\log 10\] \[=-0.3010+2\] \[=1.7\]
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