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MGIMS WARDHA MGIMS WARDHA Solved Paper-2007

  • question_answer
    In acidic medium\[MnO_{4}^{-}\]is converted to\[M{{n}^{2+}}\]. The quantity of electricity in faraday required to reduce 0.5 mole of \[MnO_{4}^{-}\]to\[M{{n}^{2+}}\]would be

    A)  2.5                                        

    B)  1

    C)  5                                            

    D)  0.5

    Correct Answer: A

    Solution :

                     In\[Mn{{O}_{4}}\]the oxidation number of\[Mn\]is +7. \[\therefore \]  \[\overset{+7}{\mathop{Mn}}\,+5{{e}^{-}}\xrightarrow{{}}\overset{+2}{\mathop{Mn}}\,\] In the reaction 5 electrons are involved. Hence, 5 faraday will be needed for the reduction of 1 mole of\[MnO_{4}^{-}\]. Therefore, for 0.5 mole of \[MnO_{4}^{-}\]number of faraday required = 2.5 F


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