A) \[XeO{{F}_{4}}\]
B) \[Xe{{O}_{2}}{{F}_{2}}\]
C) \[Xe{{O}_{3}}\]
D) \[Xe{{O}_{3}}\]
Correct Answer: C
Solution :
The end product of the hydrolysis of\[Xe{{F}_{6}}\]is \[Xe{{O}_{3}}\]. \[Xe{{O}_{6}}\xrightarrow[-2HF]{+{{H}_{2}}O}XeO{{F}_{4}}\xrightarrow[-2HF]{+{{H}_{2}}O}Xe{{O}_{2}}{{F}_{2}}\xrightarrow[-2HF]{+{{H}_{2}}O}Xe{{O}_{3}}\]
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