2. Solved Papers
  3. MGIMS WARDHA

MGIMS WARDHA MGIMS WARDHA Solved Paper-2008

  • question_answer
    Solubility product of a salt AB is\[1\times {{10}^{-8}}{{M}^{2}}\]in a solution in which the concentration of\[{{A}^{+}}\]ions is\[{{10}^{-3}}M\]. The salt will precipitate when the concentration of\[{{B}^{-}}\]ions is kept

    A) between\[{{10}^{-8}}M\text{ }to\text{ }{{10}^{-7}}M\]

    B) between\[{{10}^{-7}}M\text{ }to\text{ }{{10}^{-8}}M\]

    C) \[>{{10}^{-5}}M\]

    D) \[>{{10}^{-8}}M\]

    Correct Answer: C

    Solution :

    A salt is precipitated only when the product of ionic concentration is more than its solubility product. \[{{K}_{sp}}=1\times {{10}^{-8}}\]                 \[[{{A}^{+}}]={{10}^{-3}}M\]                 \[[{{B}^{+}}]=\frac{1\times {{10}^{-8}}}{{{10}^{-3}}}={{10}^{-5}}M\] So, AB will be precipitated only when the concentration of\[[{{B}^{-}}]\]is more than\[{{10}^{-5}}M\].


You need to login to perform this action.
You will be redirected in 3 sec spinner