A) anhydrous\[AlC{{l}_{3}}\]
B) \[FeC{{l}_{3}}\]
C) anhydrous\[ZnC{{l}_{2}}\]
D) \[Cu\]
Correct Answer: C
Solution :
\[-OH\]group is converted into\[Cl\]group by \[SOC{{l}_{2}}\]or anhy\[ZnC{{l}_{2}}\]/conc\[HCl\]or\[HCl\]etc.
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