A) 20%
B) 80%
C) 95%
D) 89%
Correct Answer: C
Solution :
The strength of solution is given by x\[c=\frac{\theta }{l\times s}\]. where the symbols have their usual meanings. Here, \[\theta =19{}^\circ ,\text{ }l=20\text{ }cm=0.20m,\] \[s=0.5\,\deg \,{{m}^{2}}/kg.\] \[\therefore \] \[c=\frac{19}{0.20\times 0.5}=190kg-{{m}^{-3}}\] The sugar sample dissolved in a\[{{m}^{3}}\]of water is 200 kg in which 190 kg is pure sugar. Therefore, purity is \[=\frac{190}{200}\times 100\] \[=95%\]
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