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MGIMS WARDHA MGIMS WARDHA Solved Paper-2008

  • question_answer
    Two identical capacitors each of capacitance 5 \[\mu F\] are charged to potentials 2 kV and 1 kV respectively. Their -ve ends are connected together. When the +ve ends are also connected together, the loss of energy of the system is

    A) 160 J                                     

    B) zero

    C) 5 J                                          

    D) 3 1.25 J

    Correct Answer: D

    Solution :

    Loss of energy \[=\frac{1}{2}\frac{{{C}_{1}}{{C}_{2}}}{({{C}_{1}}+{{C}_{2}})}{{({{V}_{1}}-{{V}_{2}})}^{2}}\] \[=\frac{1}{2}\frac{5\times {{10}^{-6}}\times 5\times {{10}^{-6}}{{(2000-1000)}^{2}}}{(5+5)\times {{10}^{-6}}}\] \[=\frac{5\times 5}{2\times 10}=1.25J\]


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