A) \[{{\sin }^{-1}}\,(0.01)\]
B) \[{{\sin }^{-1}}\,(0.0001)\]
C) \[{{\sin }^{-1}}\,(0.001)\]
D) \[{{\sin }^{-1}}\,(0.1)\]
Correct Answer: C
Solution :
In Young's double slit experiment, half angular width is given by \[\sin \theta =\frac{\lambda }{d}\] \[=\frac{589\times {{10}^{-9}}}{0.589\times {{10}^{-3}}}={{10}^{-3}}\] \[\Rightarrow \] \[\theta ={{\sin }^{-1}}(0.001)\]
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