A) 3 \[\beta \]-particles
B) 2 \[\beta \]-particles and 1 \[1\alpha \]-particle
C) 2 \[\beta \]-particles and \[1\gamma \]-particle
D) \[2\alpha \]-particles and 1 \[\beta \]-panicle
Correct Answer: B
Solution :
To form its own isotope atomic number (Z) should remain same. So, the emission of one\[\alpha -\]particle and two \[\beta -\]particles will maintain the Z same. where \[\alpha -\]particle\[{{=}_{2}}H{{e}^{4}};\]\[\beta -\]particles\[{{=}_{-1}}{{\beta }^{0}}\]
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