A) 10 m\[\Omega \] resistance is to be connected in parallel to the galvanometer
B) 10 m\[\Omega \] resistance is to be connected in series with the galvanometer
C) 0.1\[\Omega \]resistance is to be connected in D parallel to the galvanometer
D) 0.1\[\Omega \] in resistance is to be connected in series with the galvanometer
Correct Answer: A
Solution :
To convert a galvanometer into an ammeter, a shunt resistance in parallel is connected to galvanometer. Since, galvanometer G and shunt 5 are in parallel, hence \[{{i}_{g}}G=(i-{{i}_{g}})\] \[\Rightarrow \] \[S=\frac{{{i}_{g}}G}{i-{{i}_{g}}}\] \[=\frac{4\times {{10}^{-3}}\times 15}{6-4\times {{10}^{-3}}}\] \[=\frac{60\times {{10}^{-3}}}{5.996}\] \[=10\times {{10}^{-3}}\Omega \] \[=10m\Omega \]You need to login to perform this action.
You will be redirected in
3 sec