A) \[W{{m}^{-2}}{{K}^{-1}}\]
B) \[Wm\,{{K}^{-4}}\]
C) \[W{{m}^{-2}}\,{{K}^{-4}}\]
D) \[N{{m}^{-2}}\,{{K}^{-4}}\]
Correct Answer: C
Solution :
According to Stefan's law, the energy radiated per second or power radiated is given by \[P=\sigma A{{T}^{4}}\] \[\therefore \] \[\sigma =\frac{P}{A{{T}^{4}}}\] Therefore, unit of\[\sigma =\frac{W}{{{m}^{2}}{{K}^{4}}}=W{{m}^{-2}}{{K}^{-4}}\]You need to login to perform this action.
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