MGIMS WARDHA MGIMS WARDHA Solved Paper-2008

  • question_answer
    When the angle of incidence is 60° on the surface of a glass slab, it is found that the reflected ray is completely polarised. The velocity of light in glass is

    A) \[\sqrt{2}\times {{10}^{8}}m{{s}^{-1}}\]                               

    B)  \[\sqrt{3}\times {{10}^{8}}m{{s}^{-1}}\]

    C) \[2\times {{10}^{8}}m{{s}^{-1}}\]                             

    D) \[3\times {{10}^{8}}m{{s}^{-1}}\]

    Correct Answer: B

    Solution :

    Refractive index of glass, \[{{\mu }_{g}}=\tan {{\theta }_{p}}\] where\[{{\theta }_{p}}=\]polarising angle \[\Rightarrow \]                \[{{\mu }_{g}}=\tan {{60}^{o}}=\sqrt{3}\] Now,        \[{{\mu }_{g}}=\frac{c}{{{v}_{g}}}\] \[\therefore \]  \[\frac{c}{{{v}_{g}}}=\sqrt{3}\] \[\Rightarrow \]               \[{{v}_{g}}=\frac{3\times {{10}^{8}}}{\sqrt{3}}\]                 \[=\sqrt{3}\times {{10}^{8}}m/s\]


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