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MGIMS WARDHA MGIMS WARDHA Solved Paper-2008

  • question_answer
     The value of the gas constant (R) calculated from the perfect gas equation is 8.32 J/g mol-K, whereas its value calculated from the knowledge of \[{{C}_{p}}\] and \[{{C}_{v}}\] of the gas is 1.98 cal/g mol-K. From this data value of J is

    A) 4.16J/cal                              

    B) 4.18J/cal

    C) 4.20J/cal                              

    D) 4.22 J/cal

    Correct Answer: C

    Solution :

    We know that \[{{C}_{p}}-{{C}_{v}}=\frac{R}{J}\] \[\Rightarrow \]               \[J=\frac{R}{{{C}_{p}}-{{C}_{v}}}\]                 \[{{C}_{p}}-{{C}_{v}}=1.98\frac{cal}{g-mol-K}\]                 \[R=8.32\frac{J}{g-mol-K}\]                 \[J=\frac{8.32}{1.98}=4.20J/cal\]


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