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MGIMS WARDHA MGIMS WARDHA Solved Paper-2008

  • question_answer
    If work done in increasing the size of a soap film from  \[10cm\times 6cm\]to \[10cm\times 11cm\]is \[2\times {{10}^{-4}}J\]then surface tension is

    A) \[2\times {{10}^{-2}}N{{m}^{-1}}\]                          

    B) \[2\times {{10}^{-4}}N{{m}^{-1}}\]

    C) \[2\times {{10}^{-6}}N{{m}^{-1}}\]                          

    D) \[2\times {{10}^{-8}}N{{m}^{-1}}\]

    Correct Answer: A

    Solution :

    \[T=\frac{W}{\Delta A}\] \[=\frac{2\times {{10}^{-4}}}{2(50\times {{10}^{-4}})}\]                 \[=2\times {{10}^{-2}}N/m\]


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