A) conc\[{{H}_{2}}S{{O}_{4}}\]
B) \[Zn-Hg\]/cone\[HCl\]
C) aq\[KOH\]
D) ale\[KOH\]
Correct Answer: B
Solution :
In Clemmensen's reduction Zn- Hg/ cone\[HCl\]is used. \[C=O+4H\xrightarrow{Zn-Hg+conc\,HCl}C{{H}_{2}}+{{H}_{2}}O\] This method is used to convert carbonyl compound into alkane.
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