A) \[n=4,\text{ }l=1,\text{ }m=0,\text{ }s=+\frac{1}{2}\]
B) \[n=4,\text{ }l=3,\text{ }m=-3,\text{ }s=-\frac{1}{2}\]
C) \[n=4,\text{ }l=1,\text{ }m=+2,\text{ }s=-\frac{1}{2}\]
D) \[n=4,\text{ }l=0,\text{ }m=0,\text{ }s=-\frac{1}{2}\]
Correct Answer: C
Solution :
If the value of principal quantum number,\[n=4\]then the values of\[l=0\]to\[(n-1)\] =0,1,2,3 value of m depends on\[l\] If \[l=0,~~~m=0\] \[l=1,~~\,\,\,m=-1,0,+1\] \[l=2,~\,\,\,~m=-2-1,0,+1,+2\] \[l=3,\,\,\,\,\,m=-3,-2,-1,0,+1,+2,+3\] and for each value of m, the value of s is\[\pm \frac{1}{2}\]Thus, option (c) is not possible because value of m is always less than that of\[l\].
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