A) 99.8cm
B) 99cm
C) 100 cm
D) None of the above
Correct Answer: B
Solution :
\[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \] \[l=\frac{g{{T}^{2}}}{4{{\pi }^{2}}}=\frac{9.8\times 4}{4{{\pi }^{2}}}\] \[=99\,cm\]
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