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MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    Certain neutron stars are believed to be rotating at about 1 rev /s. If such a star has a radius of 20 km, the acceleration of an object on the equator of the star will be

    A) \[20\times {{10}^{8}}m/{{s}^{2}}\]                          

    B)  \[8\times {{10}^{s}}m/{{s}^{2}}\]

    C)  \[120\times {{10}^{s}}m/{{s}^{2}}\]                       

    D)  \[4\times {{10}^{8}}m/{{s}^{2}}\]

    Correct Answer: B

    Solution :

                     \[a={{\omega }^{2}}r=4{{\pi }^{2}}{{v}^{2}}r\] \[=4\times {{\pi }^{2}}\times {{1}^{2}}\times 20\times {{10}^{3}}\] \[\therefore \]  \[a=8\times {{10}^{5}}m/{{s}^{2}}\]


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