A) \[5\times {{10}^{-10}}J/C\]
B) \[3\times {{10}^{-7}}J/C\]
C) \[7\times {{10}^{-11}}J/C\]
D) \[2.5\times {{10}^{2}}J/C\]
Correct Answer: C
Solution :
\[e{{V}_{s}}=\frac{1}{2}mv_{m}^{2}\] \[{{V}_{s}}=\frac{mv_{m}^{2}}{2e}=\frac{v_{m}^{2}}{2(e/m)}\] \[=\frac{{{(4.8)}^{2}}}{2\times 1.76\times {{10}^{11}}}\] \[=7\times {{10}^{-11}}J/C\]You need to login to perform this action.
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