A) 0.05 M
B) 0.2 M
C) 0.4 M
D) 0.1M
Correct Answer: D
Solution :
\[\Rightarrow \]Molarity,\[M=\frac{N}{2}\] [where, N = normality] \[\therefore \]Molarity of\[0.2\text{ }N\text{ }N{{a}_{2}}C{{O}_{3}}\] solution\[=\frac{0.2}{2}=0.1M\]You need to login to perform this action.
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