A) m
B) 2m
C) m/2
D) 4m
Correct Answer: B
Solution :
\[\frac{mg}{A}=\frac{2T}{R}\] \[\Rightarrow \] \[\frac{mg}{\pi {{r}^{2}}}=\frac{2T\cos \theta }{r}\] \[\Rightarrow \] \[\frac{m}{r}=\frac{2\pi T\cos \theta }{g}=cons\tan t\] \[\Rightarrow \] \[\frac{m}{r}=\frac{m'}{2r}\] \[\Rightarrow \] \[m'=2m\]You need to login to perform this action.
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