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MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    A cylindrical tube, open at both ends emits a fundamental frequency\[f\]in air. The tube is dipped vertically in water, so that half of it is in water. The fundamental frequency of air column is now

    A)  \[f/2\]                                 

    B)  \[2f/4\]

    C)  \[f\]                                     

    D)  \[2f\]

    Correct Answer: C

    Solution :

                     For open organ pipe fundamental frequency\[f=\frac{v}{2l}\]. When tube is half immersed in water, the organ pipe becomes closed and length of vibrating air column becomes half (ie,\[l/2\]), \[\therefore \]New fundamental frequency \[f=\frac{v}{4\left( \frac{l}{2} \right)}=\frac{v}{2l}=f\]


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